LeetCode刷题之旅——(数据库）175. 组合两个表

LeetCode刷题之旅——(数据库）175. 组合两个表

难度：简单
题目：
**表1: Person

±------------±--------+
| 列名 | 类型 |
±------------±--------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
±------------±--------+
PersonId 是上表主键
表2: Address

±------------±--------+
| 列名 | 类型 |
±------------±--------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
±------------±--------+
AddressId 是上表主键

编写一个 SQL 查询，满足条件：无论 person 是否有地址信息，都需要基于上述两表提供 person 的以下信息：

FirstName, LastName, City, State**

题解：MySQL

# Write your MySQL query statement below
select FirstName, LastName, City, State
from Person left join Address
on Person.PersonId = Address.PersonId

测试用例：

{"headers": {"Person": ["PersonId", "LastName", "FirstName"], "Address": ["AddressId", "PersonId", "City", "State"]}, "rows": {"Person": [[1, "Wang", "Allen"]], "Address": [[1, 2, "New York City", "New York"]]}}

执行结果：

{"headers": ["FirstName", "LastName", "City", "State"], "values": [["Allen", "Wang", null, null]]}