把一个内容为16进制 的文本文件,转换成10进制的文本文件
- #include "stdafx.h"
- #include <stdio.h>
- #include <math.h>
- #include <iostream>
- #include <fstream>
- using namespace std;
- int PowerXY(int x, int y)
- {
- if(y == 0)
- return 1 ;
- else
- return x * PowerXY(x, y -1 ) ;
- }
- int Convert16To10(int number)
- {
- int r = 0 ;
- int i = 0 ;
- int result = 0 ;
- while(number)
- {
- r = number % 16 ;
- result += r * PowerXY(16, i++) ;
- number /= 16 ;
- }
- return result ;
- }
- int main()
- {
- int sum=0;
- FILE *fp,*wp;
- int i=0;
- int x;
- if((fp=fopen("cascade.txt","r"))==NULL)
- {
- printf("cannot open file");
- return -1;
- }
- if((wp=fopen("text.txt","w"))==NULL)
- {
- printf("cannot open file");
- return -1;
- }
- printf("Results:\n");
- int resutlt=0;
- while(!feof(fp))
- {
- sum++;
- fscanf(fp,"%x",&x);
- resutlt = Convert16To10(x);
- fprintf(wp,"%d ,",resutlt);
- if (sum%16==0)
- {
- fwrite("\n",1,1,wp);//换行
- }
- }
- fclose(fp);
- fclose(wp);
- return 0;
- }
假如cascade.txt 文件内容类似下面这样的:
13 00 00 00 07 00 00 00 14 E4 EB 5B 7B D9 55 3F
61 CA 3C C9 88 D1 54 3F 9A C4 D2 20 02 97 42 3F
8A 5A 62 B1 C2 37 41 3F B2 01 22 0E 23 CE 44 3F
38 8C 96 C4 D8 90 2F 3F 3B C6 87 6C 2F 88 39 3F
93 90 C9 5B 0E F1 38 3F FF 09 2E 56 D4 E0 14 C0
01 00 00 00 00 00 00 00 00 00 00 00 02 00 00 00
04 00 00 00 FF FF FF FF 01 00 00 00 FF FF FF FF
0D 00 00 00 FF FF FF FF 33 FE 7D C6 85 83 FD 3F
00 00 00 00 00 00 00 00 15 00 00 00 16 00 00 00
17 00 00 00 FF FF FF FF 02 00 00 00 FF FF FF FF
0C 00 00 00 FF FF FF FF A7 96 AD F5 45 E2 1A 40
该程序使用C++实现,将一个包含16进制数的文本文件(cascade.txt)读取并转换成10进制数,结果输出到新的文本文件(text.txt)中。主要通过Convert16To10函数完成16进制到10进制的转换,使用fscanf和fprintf进行文件读写操作。
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