Strange fuction
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4118 Accepted Submission(s): 2960
Problem Description
Now, here is a fuction:
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has only one real numbers Y.(0 < Y <1e10)
Output
Just the minimum value (accurate up to 4 decimal places),when x is between 0 and 100.
Sample Input
2 100 200
Sample Output
-74.4291 -178.8534
Author
Redow
二分法,但是是导函数的二分!注意这一点!
#include<cstdio>
#include<iostream>
#include<cmath>
using namespace std;
double y;
double deal(double n)
{
return 42*pow(n,6)+48*pow(n,5)+21*pow(n,2)+10*n-y;
}//导函数
int main()
{
int t;
double l,r,mid;
cin>>t;
while(t--)
{
l=0.0;r=100.0;
cin>>y;
while(r-l>1e-6)
{
mid=(l+r)/2;
if(deal(mid)<0)
{
l=mid;
}
else
{
r=mid;
}
}//趋向于0导函数值最小!
printf("%.4lf\n",6*pow(mid,7)+8*pow(mid,6)+7*pow(mid,3)+5*pow(mid,2)-y*mid);
}
}