Can you solve this equation?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11155 Accepted Submission(s): 5135
Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2 100 -4
Sample Output
1.6152 No solution!
Author
Redow
二分法!
#include<cstdio>
#include<iostream>
#include<iomanip>
#include<cmath>
using namespace std;
double del(double n)
{
return 8*pow(n,4)+7*pow(n,3)+2*pow(n,2)+3*n+6;
}
int main()
{
int t;
double l,r,mid,y;
scanf("%d",&t);
while(t--)
{
mid=0;
scanf("%lf",&y);
l=0.0;r=100.0;
if(del(0.0)>y||del(100.0)<y)//如果不在范围内
{
cout<<"No solution!"<<endl;
}
else
{
while(r-l>1e-6)//因为计算机默认精度为10^-6
{
mid=(l+r)/2;
if(del(mid)>y)
{
r=mid;
}
else
{
l=mid;
}
}
printf("%.4lf\n",mid);
}
}
}