1065 A+B and C (64bit)-PAT甲级

题目描述

Given three integers A, B and C in [-263, 263), you are supposed to tell whether A+B > C.

 

输入描述:

The first line of the input gives the positive number of test cases, T (<=1000).  Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

 

输出描述:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

 

输入例子:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

 

输出例子:

Case #1: false
Case #2: true
Case #3: false

用long long类型，在指定的范围中可能会有溢出的情况，需要特殊处理。

满分代码如下：

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
ll a,b,c;
int main(){
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	int n;
	cin>>n;
	ll sum;
	for(int i=1;i<=n;i++){
		cin>>a>>b>>c;
		sum=a+b;
		if(a>0&&b>0&&sum<=0){
			cout<<"Case #"<<i<<":"<<" true"<<endl;
		}else if(a<0&&b<0&&sum>=0){
			cout<<"Case #"<<i<<":"<<" false"<<endl;
		}else if(sum>c){
			cout<<"Case #"<<i<<":"<<" true"<<endl;
		}else if(sum<=c){
			cout<<"Case #"<<i<<":"<<" false"<<endl;
		}
	}
	
	return 0;
}