把一串16进制数-[UInt8],例如 01 10 CD 转成字符串-String "0110CD",代码如下:
func bytesToStr(bytes:[UInt8]) -> String {
var hexStr = ""
for index in 0 ..< bytes.count {
var Str = bytes[index].description
if Str.count == 1 {
Str = "0 "+Str;
}else {
let low = Int(Str)!%16
let hight = Int(Str)!/16
Str = hexIntToStr(HexInt: hight) + hexIntToStr(HexInt: low)
}
hexStr += Str
}
return hexStr
}
func hexIntToStr(HexInt:Int) -> String {
var Str = ""
if HexInt>9 {
switch HexInt{
case 10:
Str = "A"
break
case 11:
Str = "B"
break
case 12:
Str = "C"
break
case 13:
Str = "D"
break
case 14:
Str = "E"
break
case 15:
Str = "F"
break
default:
Str = "0"
}
}else {
Str = String(HexInt)
}
return Str
}

本文介绍了一种将16进制数数组转换为字符串的方法,使用Swift编程语言实现。通过遍历数组,将每个单元转换为其十六进制表示,并拼接成完整的字符串。
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