POJ 1017 Packets

最新推荐文章于 2022-11-28 14:14:36 发布

原创最新推荐文章于 2022-11-28 14:14:36 发布 · 198 阅读

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本文展示了一个使用C++编写的程序实例，通过一系列数学运算处理六个输入整数，并计算最终的输出结果。程序中涉及变量操作、条件判断及循环结构等关键编程概念。

Source Code

#include<iostream>
using namespace std;
int main()
{
	int x1, x2, x3, x4, x5, x6;
	while (cin >> x1 >> x2 >> x3 >> x4 >> x5 >> x6 && (x1 + x2 + x3 + x4 + x5 + x6))
	{
		long long sum = x6 + x5 + x4 + x3 / 4; x3 = x3 % 4;
		x1 = x1 - x5 * 11;
		x2 = x2 - x4 * 5;
		if (x2 < 0) x1 = x1 + x2 * 4;
		if (x1 < 0) x1 = 0;
		if (x2 < 0) x2 = 0;
		if (x3 == 1)
		{
			sum++; x2 = x2 -5;
			x1 = x1 - 7;
			if (x2 < 0) x1 = x1 + x2 * 4;
			if (x1 < 0) x1 = 0;
			if (x2 < 0) x2 = 0;
			sum = sum + (4 * x2 + x1) / 36;
			if ((4 * x2 + x1) % 36 > 0) sum++;
		}
		else if (x3 == 2)
		{
			sum++; x2 = x2 -3;
			x1 = x1 -6;
			if (x2 < 0) x1 = x1 + x2 * 4;
			if (x1 < 0) x1 = 0;
			if (x2 < 0) x2 = 0;
			sum = sum + (4 * x2 + x1) / 36;
			if ((4 * x2 + x1) % 36 > 0) sum++;
		}
		else if (x3 == 3)
		{
			sum++; x2 = x2 - 1;
			x1 = x1 - 5;
			if (x2 < 0) x1 = x1 + x2 * 4;
			if (x1 < 0) x1 = 0;
			if (x2 < 0) x2 = 0;
			sum = sum + (4 * x2 + x1) / 36;
			if ((4 * x2 + x1) % 36 > 0) sum++;
		}
		else
		{
			sum = sum + (4 * x2 + x1) / 36;
			if ((4 * x2 + x1) % 36 > 0) sum++;
		}
		cout << sum << endl;
	}
	return 0;
}