希尔排序与堆排序

输入n个数,对这n个数升序排列
希尔排序;时间复杂度O(n^3/2);
#include<iostream>
using namespace std;
int main()
{
    int T; cin >> T;
    while (T--)
    {
        int n; cin >> n;
        int a[100001];
        for (int i = 1; i <= n; i++)
            cin >> a[i];
        for (int gap = n / 2; gap > 0; gap = gap / 2)
        {
            for (int i = 0; i < gap; i++)
            {
                for (int j = i + gap; j <= n; j=j+gap)
                {
                    if (a[j] < a[j - gap])
                    {
                        int t = a[j], k = j - gap;
                        while (k > 0 && a[k] > t)
                        {
                            a[k + gap] = a[k];
                            k = k - gap;
                        }
                        a[k + gap] = t;
                    }
                }
            }
        }
        for (int i = 1; i <= n; i++)
        {
            if (i == n) cout << a[i] << endl;
            else cout << a[i] << ' ';
        }
    }
    return 0;
}
堆排序;时间复杂度O(n*log2 n);
#include<iostream>
#include<algorithm>
int a[100004], s;
using namespace std;
int main()
{
    void insert(int);
    void delet();
    int T; cin >> T;
    while (T--)
    {
        int n; cin >> n; s = n;
        for (int i = 1; i <= n; i++)
        {
            cin >> a[i];
            insert(i);
        }
        for (int p = 1; p <= n; p++)
        {
            if (p == n)cout << a[1] << endl;
            else cout << a[1] << ' ';
            delet();
        }
    }
    return 0;
}
void insert(int w)
{
    for (int j = 1; ; j++)
    {
        if (w <=1) return;
        if (a[w] < a[w / 2])
        {
            swap(a[w], a[w / 2]); w = w / 2;
        }
        else return;
    }
}
void delet()
{
    a[1] = a[s]; s--; int k = 1;
    for (int j = 1; ; j++)
    {
        if (2 * k > s) return;
        else if (2 * k == s)
        {
            if (a[k] > a[2 * k])
                swap(a[k], a[2 * k]); k = 2 * k;
        }
        else if (a[k] > a[2 * k] || a[k] > a[2 * k + 1])
        {
            if (a[2 * k] < a[2 * k + 1])
            {
                swap(a[k], a[2 * k]); k = 2 * k;
            }
            else
            {
                swap(a[k], a[2 * k + 1]); k = 2 * k + 1;
            }
        }
        else return;
    }
}

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