求一个数二进制1的个数

//求一个数二进制1的个数
#include<stdio.h>
int main()
{
    int num = 10;
    int count = 0;
    while (num)
    {
        if (num % 2 == 1)
            count++;
            num = num / 2;
    }
    printf("count=%d\n", count);
    return 0;
}