Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 50203 | Accepted: 30341 |
Description
7 3 8 8 1 0 2 7 4 4 4 5 2 6 5 (Figure 1)
Input
Output
Sample Input
5 7 3 8 8 1 0 2 7 4 4 4 5 2 6 5
Sample Output
30
动态规划及空间优化
AC代码:
#include<iostream>
#include<algorithm>
#include<stdio.h>
using namespace std;
const int maxn=101;
int a[maxn][maxn];
int maxsum[maxn];
int main()
{
int n;
scanf("%d",&n);
for(int i=1;i<=n;i++)
for(int j=1;j<=i;j++)
scanf("%d",&a[i][j]);
for(int i=1;i<=n;i++)
maxsum[i]=a[n][i];
for(int i=n-1;i>=1;i--)
for(int j=1;j<=i;j++)
maxsum[j]=max(maxsum[j],maxsum[j+1])+a[i][j];
printf("%d\n",maxsum[1]);
return 0;
}