Bone Collector

最新推荐文章于 2021-02-24 17:19:16 发布
原创 最新推荐文章于 2021-02-24 17:19:16 发布 · 284 阅读 · 0 ·
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#01背包

本文介绍了一种使用C++解决0-1背包问题的方法。通过输入物品的数量、背包容量及每个物品的价值和重量，程序能够计算出能放入背包的最大价值。采用动态规划算法，遍历所有可能的组合来寻找最优解。


#include<iostream>

using namespace std;

int max(int a,int b)

{

return a>b?a:b;

}

int main()

{

int n,t,i,j,a[1005],b[1005],e,d;

cin>>t;

while(t--)

{

int c[1005]={0};

cin>>e>>d;

for(i=0;i<e;i++)

cin>>a[i];//价值

for(i=0;i<e;i++)

cin>>b[i]; //体积

for(i=0;i<e;i++)

{

for(j=d;j>=b[i];j--)

{

c[j]=max(c[j],c[j-b[i]]+a[i]);

}

}

cout<<c[d]<<endl;

}

return 0;

}

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