UVA - 488 Triangle Wave

Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld & %llu

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Description

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 Triangle Wave 

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

1

3
2

Sample Output

1
22
333
22
1

1
22
333
22

1

分析:

给出波的振幅和平率,用数字绘制出波形图。

水。

代码:

#include<iostream> #include<stdio.h> using namespace std; int main() {     int n, a, f;     cin >> n;     int cas = 0;     while( n --)     {         if( cas ++) printf("\n");         cin >> a >> f;         while( f -- )         {             for(int i = 1; i <= a; i ++)             {                 for( int j = 0; j < i; j ++)                     cout << i;                 cout << endl;             }             for(int i = a-1; i >= 1; i --)             {                 for( int j = 0; j < i; j ++)                     cout << i;                 cout << endl;             }             if( f > 0) cout << endl;         }     }     return 0; }

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