A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.
Now given an M x N
matrix, return True
if
and only if the matrix is Toeplitz.
Example 1:
Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]] Output: True Explanation: 1234 5123 9512 In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.
Example 2:
Input: matrix = [[1,2],[2,2]] Output: False Explanation: The diagonal "[1, 2]" has different elements.
Note:
matrix
will be a 2D array of integers.matrix
will have a number of rows and columns in range[1, 20]
.matrix[i][j]
will be integers in range[0, 99]
class Solution: def isToeplitzMatrix(self, matrix): """ :type matrix: List[List[int]] :rtype: bool """ for i in range(len(matrix)-1): for j in range(len(matrix[0])-1): if matrix[i][j]!=matrix[i+1][j+1]: return False return True s=Solution() m= [[1,2,3,4],[5,1,2,3],[9,5,1,2]] print(s.isToeplitzMatrix(m))class Solution {
public boolean isToeplitzMatrix(int[][] matrix) {
for (int i=0; i<matrix.length-1;i++){
for (int j=0; j<matrix[0].length-1;j++) {
if (matrix[i][j]!=matrix[i+1][j+1])
return false;
}
}
return true;
}
}