KMP+DP
DP[i]表示以i结尾的字符串包含多少个前缀
那么DP[i]=DP[fail[i]]-1;
#include <iostream>
#include<cstdio>
#include<cstring>
#define N 200005
#define mod 10007
using namespace std;
char str[N];
int fail[N];
int dp[N];
void kmp(int n){
fail[0]=-1;
for(int i=1,j=-1;i<n;i++){
if(j>=0&&str[j+1]!=str[i])
j=fail[j];
if(str[j+1]==str[i])
j++;
fail[i]=j;
}
}
int main()
{
int T,n;
scanf("%d",&T);
while(T--){
scanf("%d",&n);
scanf("%s",str);
kmp(n);
int ans=1;
dp[0]=1;
for(int i=1;i<n;i++){
if(fail[i]==-1)
dp[i]=1;
else
dp[i]=(dp[fail[i]]+1)%mod;
ans=(ans+dp[i])%mod;
}
printf("%d\n",ans);
}
return 0;
}