Simmu

表: Candidate +-----+---------+ | id | Name | +-----+---------+ | 1 | A | | 2 | B | | 3 | C | | 4 | D | | 5 | E | +-----+---------+ 表: Vote +-----+------...

# Write your MySQL query statement below select t2.name as Department, t1.name as Employee, t1.Salary from Employee t1 inner join Department t2 on t1.DepartmentId=t2.Id where (t1.Salary,t1.Departmen...

# Write your MySQL query statement below select t1.Score, count(distinct t2.Score)+1 as Rank from Scores as t1 left join Scores as t2 on t1.Score<t2.Score group by t1.ID order by Rank asc

--正确的sql select t2.*,t1.dept_no from (select * from salaries ) t2 left join (select * from dept_manager) t1 on t1.emp_no=t2.emp_no where t1.to_date='9999-01-01' and t2.to_date='9999-01-01' answer...