萌萌哒的传送门
这道题很明显,可以通过算出有多少个三元组在一条线上,总的结果减去就行。这个可以通过枚举每一个点,算出
数组其它的点跟这个点的斜率,如果斜率相同的,就意味着在同一条线上。然后就直接搞了
弱写的代码:
//package xdlove_acmer; import java.util.*; import java.io.*; import java.math.*; public class Main { static InputStream is; static PrintWriter out; static String INPUT = ""; static void solve() { int n = ni(); long ans = 1L * n * (n - 1) * (n - 2) / 6; int[] x = new int[n],y = new int[n]; Map<Double, Integer> mp = new HashMap<Double, Integer>(); for(int i = 0; i < n; i++) { x[i] = ni(); y[i] = ni(); } for(int i = 0; i < n; i++) { mp.clear(); for(int j = i + 1; j < n; j++) { if(i != j) { int nx = x[j] - x[i]; int ny = y[j] - y[i]; double k; if(nx == 0) k = 10000; else k = 1.0 * ny / nx + 1e-8; int num = 0; if(mp.containsKey(k)) { num = mp.get(k); } mp.put(k, num + 1); } } Iterator<Double> itr = mp.keySet().iterator(); while(itr.hasNext()) { int t = mp.get(itr.next()); ans -= 1L * t * (t - 1) / 2; } } out.println(ans); } public static void main(String[] args) throws Exception { long S = System.currentTimeMillis(); is = INPUT.isEmpty() ? System.in : new ByteArrayInputStream( INPUT.getBytes()); out = new PrintWriter(System.out); solve(); out.flush(); long G = System.currentTimeMillis(); tr(G - S + "ms"); } private static boolean eof() { if (lenbuf == -1) return true; int lptr = ptrbuf; while (lptr < lenbuf) if (!isSpaceChar(inbuf[lptr++])) return false; try { is.mark(1000); while (true) { int b = is.read(); if (b == -1) { is.reset(); return true; } else if (!isSpaceChar(b)) { is.reset(); return false; } } } catch (IOException e) { return true; } } private static byte[] inbuf = new byte[1024]; static int lenbuf = 0, ptrbuf = 0; private static int readByte() { if (lenbuf == -1) throw new InputMismatchException(); if (ptrbuf >= lenbuf) { ptrbuf = 0; try { lenbuf = is.read(inbuf); } catch (IOException e) { throw new InputMismatchException(); } if (lenbuf <= 0) return -1; } return inbuf[ptrbuf++]; } private static boolean isSpaceChar(int c) { return !(c >= 33 && c <= 126); } private static int skip() { int b; while ((b = readByte()) != -1 && isSpaceChar(b)) ; return b; } private static double nd() { return Double.parseDouble(ns()); } private static char nc() { return (char) skip(); } private static String ns() { int b = skip(); StringBuilder sb = new StringBuilder(); while (!(isSpaceChar(b))) { // when nextLine, (isSpaceChar(b) && b != // ' ') sb.appendCodePoint(b); b = readByte(); } return sb.toString(); } private static char[] ns(int n) { char[] buf = new char[n]; int b = skip(), p = 0; while (p < n && !(isSpaceChar(b))) { buf[p++] = (char) b; b = readByte(); } return n == p ? buf : Arrays.copyOf(buf, p); } private static char[][] nm(int n, int m) { char[][] map = new char[n][]; for (int i = 0; i < n; i++) map[i] = ns(m); return map; } private static int[] na(int n) { int[] a = new int[n]; for (int i = 0; i < n; i++) a[i] = ni(); return a; } private static int[] copy_int(int a[]) { int[] b = new int[a.length]; for(int i = 0; i < a.length; i++) b[i] = a[i]; return b; } private static int[] unique(int a[]) { int nl = 1; int[] c; for(int i = 1; i < a.length; i++) { if(a[i] != a[nl - 1]) a[nl++] = a[i]; } c = new int[nl]; for(int i = 0; i < nl; i++) c[i] = a[i]; return c; } private static int ni() { int num = 0, b; boolean minus = false; while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ; if (b == '-') { minus = true; b = readByte(); } while (true) { if (b >= '0' && b <= '9') { num = num * 10 + (b - '0'); } else { return minus ? -num : num; } b = readByte(); } } private static long nl() { long num = 0; int b; boolean minus = false; while ((b = readByte()) != -1 && !((b >= '0' && b <= '9') || b == '-')) ; if (b == '-') { minus = true; b = readByte(); } while (true) { if (b >= '0' && b <= '9') { num = num * 10 + (b - '0'); } else { return minus ? -num : num; } b = readByte(); } } private static void tr(Object... o) { if (INPUT.length() != 0) System.out.println(Arrays.deepToString(o)); } }