198. 打家劫舍
题目链接:LeetCode
文档讲解:代码随想录
状态:AC
Java代码:
class Solution {
public int rob(int[] nums) {
if (nums.length == 1) {
return nums[0];
}
int[] dp = new int[nums.length];
dp[0] = nums[0];
dp[1] = Math.max(nums[0], nums[1]);
for (int i = 2; i < nums.length; i++) {
dp[i] = Math.max(dp[i - 1], dp[i - 2] + nums[i]);
}
return dp[nums.length - 1];
}
}
213. 打家劫舍 II
题目链接:LeetCode
文档讲解:代码随想录
状态:AC
Java代码:
class Solution {
public int rob(int[] nums) {
int len = nums.length;
if (len == 1) {
return nums[0];
}
int res1 = robHelper(nums, 1, len - 1);
int res2 = robHelper(nums, 0, len - 2);
return Math.max(res1, res2);
}
private int robHelper(int[] nums, int start, int end) {
if (start == end) {
return nums[start];
}
int[] dp = new int[nums.length];
dp[start] = nums[start];
dp[start + 1] = Math.max(nums[start], nums[start + 1]);
for (int i = start + 2; i <= end; i++) {
dp[i] = Math.max(dp[i - 1], dp[i - 2] + nums[i]);
}
return dp[end];
}
}
337. 打家劫舍 III
题目链接:LeetCode
文档讲解:代码随想录
状态:AC
Java代码:
class Solution {
public int rob(TreeNode root) {
int[] res = robTree(root);
return Math.max(res[0], res[1]);
}
int[] robTree(TreeNode root) {
if (root == null) {
return new int[]{0, 0};
}
int[] left = robTree(root.left);
int[] right = robTree(root.right);
int robFalse = Math.max(left[0], left[1]) + Math.max(right[0], right[1]);
int robTrue = root.val + left[0] + right[0];
return new int[]{robFalse, robTrue};
}
}