fastjson使用问题

public class PlayerVo implements Serializable {

    private static final long serialVersionUID = -5248543655901813565L;

    private HeroListVo heroListVo;

    public HeroListVo getHeroListVo() {
        if (heroListVo == null) {
            heroListVo = new HeroListVo(this);
        }

        return heroListVo;
    }

    @Override
    public String toString() {
        return JSON.toJSONString(this);
    }
}

public static void main(String[] args) {

    PlayerVo playerVo = new PlayerVo();
}

这里需要注意一点，new PlayerVo()会导致getHeroListVo被调用

如果向避免getHeroListVo被调用，只需要去掉toString中Json.toJsonString(this)即可