checkio (Brackets)

最新推荐文章于 2024-04-15 22:05:00 发布

原创最新推荐文章于 2024-04-15 22:05:00 发布 · 1.7k 阅读

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本文探讨如何通过算法判断给定表达式中括号的正确匹配性，涉及不同类型的括号组合，如花括号、圆括号和方括号。通过实例演示算法应用，确保表达式的逻辑性和准确性。

You are given an expression with numbers, brackets and operators. For this task only the brackets matter. Brackets come in three flavors: "{}" "()" or "[]". Brackets are used to determine scope or to restrict some expression. If a bracket is open, then it must be closed with a closing bracket of the same type. The scope of a bracket must not intersected by another bracket. For this task, you should to make a decision to correct an expression or not based on the brackets. Do not worry about operators and operands.

Input: An expression with different of types brackets. A string (unicode).

Output: The correctness the expression or don’t. A boolean.

Example:

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         checkio("((5+3)*2+1)")==True
        
         checkio("{[(3+1)+2]+}")==True
        
         checkio("(3+{1-1)}")==False
        
         checkio("[1+1]+(2*2)-{3/3}")==True
        
         checkio("(({[(((1)-2)+3)-3]/3}-3)")==False
        
         checkio("2+3")==True

How it is used: When you write code or complex expressions in a mathematical package, you can get huge headache when it comes to excess or missing brackets. This concept can be useful for your own IDE.

Precondition: There are only brackets ("{}" "()" or "[]"), digits or operators ("+" "-" "*" "/").
0 < |expression| < 10³

判断括号是否匹配，不好好思考还挺容易写错的，换了3个思路才过。

record = {}

def check(expression, target1, target2):
    tag1 = tag2 = None
    reverse_expression = expression[::-1]
    tag1 = expression.find(target1)
    tag2 = reverse_expression.find(target2)
    if tag1 == -1 and tag2 == -1:
        return True
    if tag2 == -1 or tag1 == -1:
        return False
    tag2 = len(expression)-tag2-1
    return checkio(expression[tag1+1:tag2])

def checkio(expression):
    if expression in record:
        return record[expression]
    record[expression] = check(expression, '(', ')') and check(expression, '[', ']') and check(expression, '{', '}')
    return record[expression]


print checkio('(((([[[{{{3}}}]]]]))))')
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio(u"((5+3)*2+1)") == True, "Simple"
    assert checkio(u"{[(3+1)+2]+}") == True, "Different types"
    assert checkio(u"(3+{1-1)}") == False, ") is alone inside {}"
    assert checkio(u"[1+1]+(2*2)-{3/3}") == True, "Different operators"
    assert checkio(u"(({[(((1)-2)+3)-3]/3}-3)") == False, "One is redundant"
    assert checkio(u"2+3") == True, "No brackets, no problem"

一个非常美的代码，虽然效率不高

def checkio(Expression):
    'Check expression for correct brackets order'
    x = "".join(a for a in Expression if a in "{}()[]")
    while ("()" in x) or ("[]" in x) or ("{}" in x):
        x=x.replace("()","")
        x=x.replace("{}","")
        x=x.replace("[]","")
    return len(x)==0