计算n的阶乘:
double factorial(int n)
{
double result = 1.0;
for (int i = 1; i <= n; i++)
{
result = result * i;
}
return result;
}
计算x的几次方相加
double shucheng(int n,double x)
{
double result = 1.0;
for(int i = 0;i<n;i++)
{
result = result*x;
}
return result;
}