1058 A+B in Hogwarts (20 分)

哈利波特魔法货币计算器
本文介绍了一个基于哈利波特系列小说中魔法世界货币系统的计算器程序。该程序能够将两种以加隆、西可和纳特为单位的魔法货币进行相加,并以相同的格式输出结果。输入的货币形式为Galleon.Sickle.Knut,其中加隆范围在0到10^7,西可范围在0到16,纳特范围在0到28。

 

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut (Galleon is an integer in [0,10​7​​], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

C++:

/*
 @Date    : 2018-02-01 19:26:08
 @Author  : 酸饺子 (changzheng300@foxmail.com)
 @Link    : https://github.com/SourDumplings
 @Version : $Id$
*/

/*
https://www.patest.cn/contests/pat-a-practise/1058
 */

#include <cstdio>

using namespace std;

long long getInput()
{
    long long G, S, K;
    scanf("%lld.%lld.%lld", &G, &S, &K);
    return K + S * 29 + G * 17 * 29;
}

void OutPut(long long kValue)
{
    long long K = kValue % 29;
    kValue /= 29;
    long long S = kValue % 17;
    long long G = kValue / 17;
    printf("%lld.%lld.%lld\n", G, S, K);
    return;
}

int main(int argc, char const *argv[])
{
    long long A = getInput();
    long long B = getInput();
    OutPut(A+B);
    return 0;
}

 

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