UVA oj 488 Triangle Wave

Triangle Wave

Time Limit: 3000MS

Memory Limit: Unknown

64bit IO Format: %lld & %llu

Submit Status

Description

Triangle Wave

In this problem you are to generate a triangular wave form according to a specified pair of Amplitude and Frequency.

Input and Output

The input begins with a single positive integer on a line by itself indicating the number of the cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive inputs.

Each input set will contain two integers, each on a separate line. The first integer is the Amplitude; the second integer is the Frequency.

For each test case, the output must follow the description below. The outputs of two consecutive cases will be separated by a blank line.

For the output of your program, you will be printing wave forms each separated by a blank line. The total number of wave forms equals the Frequency, and the horizontal ``height'' of each wave equals the Amplitude. The Amplitude will never be greater than nine.

The waveform itself should be filled with integers on each line which indicate the ``height'' of that line.

NOTE: There is a blank line after each separate waveform, excluding the last one.

Sample Input

1

3
2

Sample Output

1
22
333
22
1

1
22
333
22
1

一道水题，PE了两发，UVA的样例输入好奇葩

#include<cstdio>
#include<iostream>
#include<cstring>
#include<cstdlib>
using namespace std;

int main()
{
    int t;
    scanf("%d",&t);
    while(t--)
    {
       int x,y;
       scanf("%d%d",&x,&y);
        for(int i=1;i<=y;i++)
        {
            for(int j=1;j<=x;j++)
            {
                for(int k=1;k<=j;k++)
                {
                    printf("%d",j);
                }
                printf("\n");
            }
            for(int j=x-1;j>=1;j--)
            {
                for(int k=1;k<=j;k++)
                {
                    printf("%d",j);
                }
                printf("\n");
            }
            if(i != y)
                printf("\n");
        }
        if(t)
            printf("\n");
    }
    return 0;
}