PAT---1058. A+B in Hogwarts (20)

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本文介绍了一个基于哈利波特魔法世界货币系统的计算程序。该程序能够将两种以“加隆.西可.纳特”形式给出的货币数值相加，并以同样的格式输出结果。输入为两个字符串形式的标准货币值，输出则为它们的和。

题目要求：
If you are a fan of Harry Potter, you would know the world of magic has its own currency system – as Hagrid explained it to Harry, “Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it’s easy enough.” Your job is to write a program to compute A+B where A and B are given in the standard form of “Galleon.Sickle.Knut” (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28

参考代码：

#include <iostream>
#include <stdio.h>
using namespace std;
int main()
{
   int galleon = 17*29;
   int sickle = 29;
   long long a[6] = {0};
   scanf("%lld.%lld.%lld",&a[0],&a[1],&a[2]);
   scanf("%lld.%lld.%lld",&a[3],&a[4],&a[5]);
   long long  expect_money = a[0]*galleon + a[1]*sickle + a[2];
   long long own_money = a[3]*galleon + a[4]*sickle + a[5];
   long long money = expect_money + own_money;
   cout << money/galleon<<"."<<money/sickle%17<<"."<<money%sickle;
   return 0;
}