HDU- 2057 A + B Again

A - A + B Again

 

 

Description

There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !

 

Input

The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.

 

Output

For each test case,print the sum of A and B in hexadecimal in one line.

 

Sample Input

 

         +A -A

+1A 12

1A -9

-1A -12

1A -AA

 

Sample Output

 0

2C

11

-2C

-90

 

 

#include<stdio.h>

#include<math.h>

int main()

{

    long long a,b;

    while(scanf("%llX%llX",&a,&b)!=EOF)

    {

        if(a+b>=0)

        {

            printf("%llX\n",a+b);

        }

        else

        {

            printf("-%llX\n",-a-b);

        }

    }

    return 0;

}

 

十六进制输入输出。