java-自己的math包，还会更新

import com.sun.jmx.remote.internal.ArrayQueue;

import javax.management.openmbean.TabularDataSupport;
import java.io.*;
import java.math.BigInteger;
import java.util.*;
import java.util.stream.Collectors;

public class Main
{
    static PrintWriter pw = new PrintWriter(new BufferedWriter(new OutputStreamWriter(System.out)));
    static int mod = (int)1e9 + 7;
    static List<Long> yn = new ArrayList<>();

    static void search_factor(int n)
    {
        for(long i = 1 ; i <= Math.sqrt(n) ; i ++)
        {
            if(n % i == 0)
            {
                yn.add(i);
                yn.add(n / i);
            }
        }

        // 相同因子去重，这个方法，完美
        yn = yn.stream().distinct().collect(Collectors.toList());
    }

    public static void main(String[] args) throws IOException
    {
        int n = 6;
        math math_myself = new math();

        yn = math_myself.get_factor(n);

        for(int i = 0 ; i < yn.size() ; i ++)  pw.print(yn.get(i) + " ");
        pw.flush();
    }
}

class rd
{
    static BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    static StringTokenizer tokenizer = new StringTokenizer("");

    static String nextLine() throws IOException { return reader.readLine(); }
    static String next() throws IOException
    {
        while(!tokenizer.hasMoreTokens())  tokenizer = new StringTokenizer(reader.readLine());
        return tokenizer.nextToken();
    }
    static int nextInt() throws IOException { return Integer.parseInt(next()); }
    static double nextDouble() throws IOException { return Double.parseDouble(next()); }
    static long nextLong() throws IOException { return Long.parseLong(next()); }
    static BigInteger nextBigInteger() throws IOException
    {
        BigInteger d = new BigInteger(rd.nextLine());
        return d;
    }
}

class PII
{
    int x,y;
    public PII(int x, int y)
    {
        this.x = x;
        this.y = y;
    }
}

class math
{
    int gcd(int a,int b)
    {
        if(b == 0)  return a;
        else return gcd(b,a % b);
    }

    int lcm(int a,int b)
    {
        return a * b / gcd(a, b);
    }

    // 求n的所有约数
    List get_factor(int n)
    {
        List<Long> a = new ArrayList<>();
        for(long i = 1; i <= Math.sqrt(n) ; i ++)
        {
            if(n % i == 0)
            {
                a.add(i);
                if(i != n / i)  a.add(n / i);  // // 避免一下的情况：x = 16时，i = 4 ，x / i = 4的情况，这样会加入两种情况  ^-^复杂度能减少多少是多少
            }
        }

        // 相同因子去重，这个方法，完美
        a = a.stream().distinct().collect(Collectors.toList());

        // 对因子排序（升序）
        Collections.sort(a);

        return a;
    }

    // 判断是否是质数
    boolean check_isPrime(int n)
    {
        if(n < 2) return false;
        for(int i = 2 ; i <= n / i; i ++)  if (n % i == 0) return false;
        return true;
    }
}