Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as:
a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
Example 1:
Given the following tree [3,9,20,null,null,15,7]:
3
/ \
9 20
/ \
15 7
Return true.
Example 2:
Given the following tree [1,2,2,3,3,null,null,4,4]:
1
/ \
2 2
/ \
3 3
/ \
4 4
Return false.
class Solution {
public boolean isBalanced(TreeNode root) {
if(root == null) return true;
int left = height(root.left);
int right = height(root.right);
return Math.abs(left - right) <= 1 && isBalanced(root.left) && isBalanced(root.right);
}
public int height(TreeNode node){
int h = 0;
if(node == null) return h;
return 1 + Math.max(height(node.left), height(node.right));
}
}
本文介绍了一种判断二叉树是否为高度平衡的算法。高度平衡二叉树定义为对于树中每一个节点,其两个子树的深度相差不超过1。通过递归计算每个节点的左右子树高度并比较,实现高效判断。
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