Find the contiguous subarray within an array (containing at least one number) which has the largest sum.
For example, given the array [-2,1,-3,4,-1,2,1,-5,4]
,
the contiguous subarray [4,-1,2,1]
has the largest sum = 6
.
More practice:
If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.
solution:
DP
code:
class Solution {
public:
int maxSubArray(vector<int>& nums) {
int size=nums.size();
int sum=0;
int max=INT_MIN;
for(int i=0; i<size; i++){
sum+=nums[i];
if(sum>max){
max=sum;
}
if(sum<0){
sum=0;
}
}
return max;
}
};