1143. 最长公共子序列
常规动态规划
class Solution:
def longestCommonSubsequence(self, text1: str, text2: str) -> int:
n1, n2 = len(text1), len(text2)
dp = [[0] * (n2 + 1) for _ in range(n1 + 1)]
for i in range(1, n1 + 1):
for j in range(1, n2 + 1):
if text1[i - 1] == text2[j - 1]:
dp[i][j] = 1 + dp[i-1][j-1]
else:
dp[i][j] = max(
dp[i-1][j],dp[i][j-1]
)
return dp[-1][-1]