LeetCode 609. Find Duplicate File in System解题报告(python)

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609. Find Duplicate File in System

Find Duplicate File in System python solution

题目描述

Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups of duplicate files in the file system in terms of their paths.
A group of duplicate files consists of at least two files that have exactly the same content.
A single directory info string in the input list has the following format:
“root/d1/d2/…/dm f1.txt(f1_content) f2.txt(f2_content) … fn.txt(fn_content)”
It means there are n files (f1.txt, f2.txt … fn.txt with content f1_content, f2_content … fn_content, respectively) in directory root/d1/d2/…/dm. Note that n >= 1 and m >= 0. If m = 0, it means the directory is just the root directory.
The output is a list of group of duplicate file paths. For each group, it contains all the file paths of the files that have the same content. A file path is a string that has the following format:
“directory_path/file_name.txt”
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解析

暴力破解，将每个content都记录下来，然后统计他们出现的次数。
将出现两次及两次以上的输出。

class Solution:
    def findDuplicate(self, paths):
        M = collections.defaultdict(list)
        for line in paths:
            data = line.split()
            root = data[0]
            for file in data[1:]:
                name, _, content = file.partition('(')
                M[content[:-1]].append(root + '/' + name)
            
        return [x for x in M.values() if len(x) > 1]