模版参考:http://blog.youkuaiyun.com/non_cease/article/details/7426395
题目:给定一棵树,求两个结点的最近公共祖先。(最基础的LCA问题)
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn = 10006;
int dp[maxn][15], father[maxn], dep[maxn];
bool hash[maxn], mark[maxn];
int n;
void getDepth(int u) { //从叶节点向根求结点深度
int v = u, l = 0;
while (dep[v] < 0) {
v = father[v];
l++;
}
while (v != u) {
dep[u] = l + dep[v];
u = father[u];
l--;
}
}
//模版
void DP() {
int i, j;
memset (dp, -1, sizeof (dp));
for (i = 1; i <= n; i++)
dp[i][0] = father[i];
for (j = 1; (1<<j) <= n; j++)
for (i = 1; i <= n; i++)
//if (dp[i][j-1] != -1)
dp[i][j] = dp[dp[i][j-1]][j-1];
}
int get_nearest_ancestor(int u, int v) {
int tmp, log, i;
if (dep[u] < dep[v]) {
tmp = u; u = v; v = tmp;
}
for (log = 1; (1<<log) <= dep[u]; log++);
log--;
for (i = log; i >= 0; i--)
if (dep[u]-(1<<i) >= dep[v])
u = dp[u][i];
if (u == v) return u;
for (i = log; i >= 0; i--)
if (dp[u][i] != -1 && dp[u][i] != dp[v][i])
u = dp[u][i],v = dp[v][i];
return father[u];
}
int main()
{
int t, i, x, y;
scanf ("%d", &t);
while(t--) {
memset(hash, false, sizeof (hash));
memset(mark, false, sizeof (mark));
memset(dep, -1, sizeof (dep));
scanf ("%d", &n);
for (i = 1; i < n; i++) {
scanf ("%d%d", &x, &y);
father[y] = x;
hash[y] = true;
mark[x] = true;
}
for (i = 1; i <= n; i++)
if (!hash[i]) break;
father[i] = i;
dep[i] = 0;
for (i = 1; i <= n; i++) //遍历所有叶节点求结点的深度
if (!mark[i])
getDepth(i);
DP();
scanf ("%d %d", &x, &y);
printf("%d\n", get_nearest_ancestor(x, y));
}
return 0;
}