codeforces 468A(63/600)_polycarp plays "game 23". initially he has a numbe-优快云博客

本文介绍了一种通过数学运算使序列中的数最终变为24的游戏算法。针对不同序列长度n提出了具体的实现方案，并通过代码展示了当n为1到5时的具体操作步骤。

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Little X used to play a card game called “24 Game”, but recently he has found it too easy. So he invented a new game.

Initially you have a sequence of n integers: 1, 2, …, n. In a single step, you can pick two of them, let’s denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a × b.

After n - 1 steps there is only one number left. Can you make this number equal to 24?

Input
The first line contains a single integer n (1 ≤ n ≤ 105).

Output
If it’s possible, print “YES” in the first line. Otherwise, print “NO” (without the quotes).

If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: “a op b = c”. Where a and b are the numbers you’ve picked at this operation; op is either “+”, or “-“, or “*”; c is the result of corresponding operation. Note, that the absolute value of c mustn’t be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.

If there are multiple valid answers, you may print any of them.

Example
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24

只要超过4的都能用
人工打表美滋滋

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin>>n;
    if(n<4)
    {
        cout<<"NO";
        return 0;
    }
    cout<<"YES"<<endl;
    if(n==4)
    {
        cout<<"2 * 3 = 6\n6 * 4 = 24\n";
        cout<<"1 * 24 = 24\n";
        return 0;
    }
    if(n==5)
    {
        cout<<"5 - 1 = 4\n4 - 2 = 2\n";
        cout<<"2 * 3 = 6\n6 * 4 = 24\n";
//      cout<<"1 * 24 = 24\n";
        return 0;
    }
    if(n%2)
    {
        for(int a=6;a<n;a+=2)
        {
            printf("%d - %d = 1\n",a+1,a);
            cout<<"1 * 1 = 1\n";
        }
        cout<<"5 - 1 = 4\n4 - 2 = 2\n";
        cout<<"2 * 3 = 6\n6 * 4 = 24\n";
//      cout<<"1 * 24 = 24\n";
        return 0;
    }
    for(int a=5;a<n;a+=2)
    {
        printf("%d - %d = 1\n",a+1,a);
        cout<<"1 * 1 = 1\n";
    }
    cout<<"2 * 3 = 6\n6 * 4 = 24\n";
    cout<<"1 * 24 = 24\n";
}