Elevator
The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.
For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.
Input Specification:
Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.
Output Specification:
For each test case, print the total time on a single line.
Sample Input:
3 2 3 1
Sample Output:
41
比较简单的一道题。
#include<iostream>
#include<stdio.h>
using namespace std;
int main(){ //freopen("./in","r",stdin); int n;
scanf("%d",&n);
int i;
int temp,curTemp,preTemp=0; int totalTime=0; for(i=0;i<n;i++){ scanf("%d",&curTemp); temp=curTemp-preTemp; preTemp=curTemp; totalTime+=temp>0?temp*6:temp*4*(-1); totalTime+=5; } printf("%d",totalTime);
}

本文介绍了一个简单的电梯路径优化问题,通过给定楼层请求列表来计算完成所有请求所需的总时间。电梯从0楼开始,每向上一层花费6秒,向下一层花费4秒,并在每一站停留5秒。
484

被折叠的 条评论
为什么被折叠?



