description
Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).
Input Specification:
Each input file contains one test case. Each case contains a pair of integers a and b where −10
6
≤a,b≤10
6
. The numbers are separated by a space.
Output Specification:
For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.
Sample Input:
-1000000 9
Sample Output:
-999,991
idea
- 实现目标:把整数自低位到高位,每隔三个加一个逗号
- 根据位数规律输出,联想到借助字符串
solution
#include <stdio.h>
#include <string.h>
int main(){
int a, b;
char result[10], flag[10] = {0}, n = 0;
scanf("%d%d", &a, &b);
sprintf(result, "%d", a+b);
for(int i = strlen(result) - 1; i >= 0; i--){
if(n == 3){
n = 1;
flag[i] = 1;
}
else
n++;
}
for(int i = 0; i < strlen(result); i++){
printf("%c", result[i]);
if(result[i] != '-' && flag[i]) printf(",");
}
return 0;
}
可以哭,可以难受,但不能停止走出舒适区的行动。因为想让人生的底色是进步,而非自证预言的憾事。