问题及代码:
运行结果:
运行结果:
#include <iostream>
using namespace std;
class A
{
public:
A()
{
a=0;
}
A (int i)
{
a=i;
}
void print()
{
cout<<a<<" ";
}
private:
int a;
};
class B: public A
{
public:
B()
{
b=0;
}
B(int i, int j, int k): A(i),aa(j)
{
b=k;
}
//思考:这3处出现的print,有何区别
void print() //(1)
{
A::print(); //(2)
aa.print(); //(3)
cout<<b<<endl;
}
private:
int b;
A aa;
};
int main()
{
B test[2];
test[0]=B(1,4,7);
test[1]=B(2,5,8);
for(int i=0; i<2; i++)
test[i].print();
return 0;
} 运行结果:
问题及代码:
#include <iostream>
using namespace std;
class A
{
public:
A(char *s)
{
cout<<s<<endl;
}
};
class B:public A
{
public:
B(char *s1, char *s2):A(s1)
{
cout<<s2<<endl;
}
};
class C:public A
{
public:
C(char *s1,char *s2):A(s1)
{
cout<<s2<<endl;
}
};
class D:public B, C
{
public:
D(char *s1,char *s2,char *s3,char *s4):B(s1,s2),C(s3,s4)
{
cout<<s4<<endl;
}
};
int main()
{
D d("class A","class B","class C","class D");
return 0;
} 运行结果:
问题及代码:
#include <iostream>
using namespace std;
class Base
{
public:
Base(char i) { cout<<"Base constructor. --"<<i<<endl; }
};
class Derived1:virtual public Base
{
public:
Derived1(char i,char j):Base(i)
{
cout<<"Derived1 constructor. --"<<j<<endl;
}
};
class Derived2:virtual public Base
{
public:
Derived2(char i,char j):Base(i)
{
cout<<"Derived2 constructor. --"<<j<<endl;
}
};
class MyDerived:public Derived1,public Derived2
{
public:
MyDerived(char i,char j,char k,char l,char m,char n,char x): Derived2(i,j), Derived1(k,l), Base(m), d(n)
{
cout<<"MyDerived constructor. --"<<x<<endl;
}
private:
Base d;
};
int main()
{
MyDerived obj('A','B','C','D','E','F','G');
return 0;
} 运行结果:
本文通过三个示例深入探讨了C++中多重继承的构造过程、虚基类的使用及其如何解决菱形继承问题。示例包括成员函数重写、构造函数调用流程及虚基类的实例化。
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