23. Merge k Sorted Lists
- Total Accepted: 116272
- Total Submissions: 455841
- Difficulty: Hard
- Contributors: Admin
Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.
这题和21题类似,一开始我逐个归并,直接超时,使用二分法归并就AC,还是二分大法好啊
代码如下:
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode mergeKLists(ListNode[] lists) {
int len = lists.length;
if (len <= 0) {
return null;
}
if (len == 1) {
return lists[0];
}
while (len>1) {
int mid=(len+1)/2;
for(int i=0;i<len/2;i++)
{
lists[i]=mergeTwoLists(lists[i],lists[i+mid]);
}
len=mid;
}
return lists[0];
}
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode result = new ListNode(0);
ListNode lastNode = result;
while (l1 != null && l2 != null) {
if (l1.val < l2.val) {
lastNode.next = l1;
l1 = l1.next;
} else {
lastNode.next = l2;
l2 = l2.next;
}
lastNode = lastNode.next;
}
if (l1 != null) {
lastNode.next = l1;
} else {
lastNode.next = l2;
}
return result.next;
}
}