codility Brackets

最新推荐文章于 2018-04-22 17:25:04 发布

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本文介绍了一个用于解决Codility Lesson 7中括号匹配问题的Python函数实现。该函数通过栈来判断括号序列是否正确配对，为括号验证提供了一种高效的方法。

Question:codility Lesson7 Brackets

My Answer:

def soluton(S):
    if len(S) % 2 == 1:
        return 0

    nested = {"]":"[","}":"{",")":"("}
    half = ["[","{","("]
    stack = []

    for ele in S:
        if ele in half:
            stack.append(ele)
        else:
            if len(stack) == 0:
                return 0
            elif nested[ele] != stack.pop():
                return 0
    if len(stack) == 0:
        return 1
    else:
        return 0