大致的玩家与电脑下棋的方法便是如此,可以多观察几次
#define _CRT_SECURE_NO_WARNINGS 1
#include "Backgammon.h"
void game() {
char arr[row][col] = { 0 };//存放数组
Initinitalize(arr,row,col);//数组初始化
Display(arr, row, col);//棋盘打印
while (1) {
Pler(arr, row, col);
cls();
Display(arr, row, col);
Compler(arr, row, col);
cls();
Display(arr, row, col);
}
}
void Initinitalize(char arr1[row][col], int Row, int Col) {//数组初始化
int i = 0;
int j = 0;
for (i = 0; i < Row;i++) {
for (j = 0; j < Col; j++) {
arr1[i][j] = ' ';
}
}
}
void Display(char arr1[row][col], int Row, int Col) {//打印棋盘
int i = 0;
int j = 0;
for (i = 0; i < Row; i++) {
for (j = 0; j < Col; j++) {
printf(" %c ", arr1[i][j]);
if (j < Row - 1) {
printf("|");
}
}
printf("\n");
if (i < Row - 1) {
int j = 0;
for (j = 0; j < Col; j++) {
printf("___");
if (j < Col - 1) {
printf("|");
}
}printf("\n");
}
}
}
void cls() {
system("cls");
}
void Pler(char arr1[row][col], int Row, int Col) {//玩家进行下棋
int x = 0;
int y = 0;
printf("player move\n");
while (1) {
printf("请输入下棋的坐标\n");
scanf("%d %d", &x,&y);
if (x>=1&&x<= row&&y>=1&&y<=col) {
if (arr1[x - 1][y - 1] == ' ') {
arr1[x - 1][y - 1] = '*';
break;
}
else{
printf("此位置非空,请重新输入\n");
}
}
else {
printf("坐标非法,请重新输入\n");
}
}
}
void Compler(char arr1[row][col], int Row, int Col){//电脑下棋
printf("电脑行动\n");
while (1) {
int x = rand() % row;
int y = rand() % col;
if (arr1[x][y] == ' ') {
arr1[x][y] = '#';
break;
}
}
}