CCF12月 1 . 2 4 分别是 100 60 0 ...._2021年12月ccf题解-优快云博客

本文介绍了一种使用C++实现的交通信号灯模拟算法，该算法考虑了红绿黄三色灯的切换逻辑，以及车辆通过路口的时间计算。通过对不同颜色信号灯的等待时间和通行时间的精确计算，模拟了真实世界中车辆在遇到不同交通信号时的行为。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

#include <iostream>

using namespace std;

int main()
{
    int r, y, g;

    cin >> r >> y >> g;

    int n;

    cin >> n;

    int sum = 0;

    for(int i=0; i<n; i++){
        int ta, tb;

        cin >> ta >> tb;

        if((ta == 0) || (ta == 1)){
            sum += tb;
        }
        else if(ta == 2){
            sum += (tb + r);
        }

    }

    cout << sum << endl;
           return 0;
}






2.


#include <iostream>

using namespace std;

int main()
{
    int r, y, g;
   cin >> r >> y >> g;

    int s = r+y+g;

    int n;

    cin >> n;

    int sum = 0;
    int ta[n+5], tb[n+5];

    for(int i=0; i<n; i++){


        cin >> ta[i] >> tb[i];
    }



    for(int i=0; i<n; i++){
//on road
        if((ta[i] == 0)){
            sum += tb[i];
//                cout << sum << endl;
        }

        //yellow light
        else if(ta[i] == 2){
//            cout << sum << endl;
            int sum1 = sum%s;

            sum1 += (g + y -tb[i]);
            sum1 %= s;
      //          cout << "sum1:" << sum1 << endl;

if(sum1 >=0 && sum1 <g);
else sum += (s-sum1);


        }
        //red light
        else if(ta[i] == 1){
//            cout << sum << endl;
            int sum1 = sum%s;

            sum1 += (s-tb[i]);
            sum1 %= s;
      //          cout << "sum1:" << sum1 << endl;

if(sum1 >=0 && sum1 <g);
else sum += (s-sum1);


        }

        else if(ta[i] == 3){
//            cout << sum << endl;
            int sum1 = sum%s;

            sum1 += (g-tb[i]);
            sum1 %= s;
      //          cout << "sum1:" << sum1 << endl;
            int tmp = sum1-tb[i]-r-y;
if(sum1 >=0 && sum1 <g);
else sum += (s-sum1);


        }
//        cout << sum << endl;

    }

    cout << sum << endl;
           return 0;
}


/*
//30 30 30 3 0 12 3 13 0 12        24 
#include <iostream>

using namespace std;

int main()
{
    int r, y, g;

    cin >> r >> y >> g;

    int s = r+y+g;

    int n;

    cin >> n;

    int sum = 0;
    int ta[n+5], tb[n+5];

    for(int i=0; i<n; i++){


        cin >> ta[i] >> tb[i];
    }



    for(int i=0; i<n; i++){
//on road
        if((ta[i] == 0)){
            sum += tb[i];
//                cout << sum << endl;
        }

        //yellow light
        else if(ta[i] == 2){
            int sum1 = sum%s;
//                cout << "sum1:" << sum1 << endl;
            int tmp = sum1-tb[i]-r;

            if(tmp < 0){
              sum -= tmp;
            }
//            cout << sum << endl;
        }
        //red light
        else if(ta[i] == 1){
            int sum1 = sum%s;
//                cout << "sum1:" << sum1 << endl;
            int tmp = sum1-tb[i];
            if(tmp < 0){
              sum -= tmp;
            }
        }
        else if(ta[i] == 3){
            int sum1 = sum%s;
//                cout << "sum1:" << sum1 << endl;
            int tmp = sum1-tb[i]-r-y;

            if(tmp < 0){
              sum -= tmp;
            }
//            cout << sum << endl;
        }
//        cout << sum << endl;

    }

    cout << sum << endl;
           return 0;
}
*/


4.


#include <iostream>
#include<algorithm>
#include<queue>
#include<stack>

using namespace std;


typedef long long ll;


const int maxn = 100000+5;

struct Edge{
    int a, b, va;
}E[maxn];
int n, r, m;
int fa[maxn], deep[maxn];

priority_queue<int>q;

bool cmp(Edge a, Edge b){
    return a.va < b.va;
}

int find(int x){
    return x == fa[x]? x : find(fa[x]);
}

void unite(int a, int b){
    int faa = find(a);
    int fbb = find(b);

    if(faa == fbb)
        return;
    else{
        if(deep[faa] < deep[fbb]){
            fa[faa] = fbb;
        }
        if(deep[faa] > deep[fbb]){
            fa[fbb] = faa;
        }
        else{
            fa[fbb] = faa;
            deep[faa]++;
        }
    }
}


void Kru(){
    sort(E, E+r, cmp);
    for(int i=0; i<=r; i++){
        fa[i] = i;
        deep[i] = 0;

    }
    for(int i=0; i<r; i++){
        if(find(E[i].a) != find(E[i].b)){
            unite(E[i].a, E[i].b);
            q.push(E[i].va);
        }

    }
    return;
}

int main()
{

    int root;
    cin >> n >> r >> root;

    int dis[n+5][n+5];




    for(int i=0; i<r; i++){
        cin >> E[i].a >> E[i].b>> E[i].va;
        dis[E[i].a][E[i].b] = E[i].va;
        dis[E[i].b][E[i].a] = E[i].va;

    }

    Kru();

    //adjust
    int flag = 0;
    while(!q.empty()){
        int tmp = q.top();
        for(int i=1; i<=n; i++){
            if(dis[root][i] == tmp){
                cout << tmp << endl;
                flag = 1;
                break;
            }
        }
        if(flag){
            break;
        }
        q.pop();
    }



    return 0;
}