hdu--5665--Lucky

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Lucky

 
 Accepts: 819
 
 Submissions: 2299
 Time Limit: 2000/1000 MS (Java/Others)
 
 Memory Limit: 65536/65536 K (Java/Others)
问题描述
\ \ \ \    Vampire喜欢玄学,尤其喜欢研究幸运数字.

\ \ \ \    对于一个数字集合S,定义关于S的幸运数字为无法用S中的数相加得到的最小的非负整数(每个数可以使用任意次).

\ \ \ \    现在给定一个数集,如果能使用其中的数相加得到任意自然数,输出”YES”,否则输出”NO”.
输入描述
\ \ \ \    第一行一个正整数T,为数据组数.

\ \ \ \    每组数据第一行一个n,表示集合大小.

\ \ \ \    接下来n个数,表示该数集里的数.

\ \ \ \ 1\le n\le 10^5,1\le T \le 10,0\le a_i \le 10^9    1≤n≤10​5​​,1≤T≤10,0≤a​i​​≤10​9​​.
输出描述
\ \ \ \    每组数据回答一个”YES”或”NO”.
输入样例
1
1
2
输出样例
NO

分析:细想一下,只要有 0 和 1 即可经过 n 次加法得到任意非负整数。

代码如下:

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>
#include <queue>
using namespace std;
#define N 102000
#define inf 0x3f3f3f3f
int s[N], cp[N];
int main()
{
#ifdef OFFLINE
    freopen("t.txt", "r", stdin);
#endif
    int i, j, n, t, m;
    scanf("%d", &t);
    while (t--){
        scanf("%d", &n);
        bool zero = false, one = false;
        for (i = 0; i < n; i++){
            scanf("%d", &m);
            if (m == 0)  zero = true;
            if (m == 1)    one = true;
        }
        if (zero&&one)
            puts("YES");
        else
            puts("NO");
    }
    return 0;
}


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由于很久没使用 ftp 登录阿里云的服务器了,导致我忘了账号和密码,怎么尝试都失败。于是打算重新创建用户来登录 ftp 。现在就只能登录 xshell 了,这个的用户名可以使用 root 登录,密码的话就在阿里云控制台那里可以查到,也可以重置密码。然后现在就能登入 xshell 进行用户创建了。百度之后的命令如下: 1、安装 vsftpd  查看是否已经安装 vsftpd 的命令如下: rp

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