题目描述
Consider all the leaves of a binary tree. From left to right order, the values of those leaves form a leaf value sequence.

For example, in the given tree above, the leaf value sequence is (6, 7, 4, 9, 8).
Two binary trees are considered leaf-similar if their leaf value sequence is the same.
Return true if and only if the two given trees with head nodes root1 and root2 are leaf-similar.
Note:
Both of the given trees will have between 1 and 100 nodes.
方法思路
class Solution {
//Runtime: 2 ms, faster than 95.33%
//Memory Usage: 37.3 MB, less than 10.51%
public boolean leafSimilar(TreeNode root1, TreeNode root2) {
List<Integer> leaves1 = new ArrayList();
List<Integer> leaves2 = new ArrayList();
dfs(root1, leaves1);
dfs(root2, leaves2);
return leaves1.equals(leaves2);
}
public void dfs(TreeNode node, List<Integer> leafValues) {
if (node != null) {
if (node.left == null && node.right == null)
leafValues.add(node.val);
dfs(node.left, leafValues);
dfs(node.right, leafValues);
}
}
}

本文介绍了一种算法,用于判断两棵二叉树是否具有相同的叶子节点序列。通过深度优先搜索遍历树结构,收集所有叶子节点的值,并比较两个序列是否相等来实现。适用于1到100个节点的二叉树。
391

被折叠的 条评论
为什么被折叠?



