PAT 1083 List Grades (25)

最新推荐文章于 2022-01-20 12:03:50 发布

原创最新推荐文章于 2022-01-20 12:03:50 发布 · 198 阅读

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本篇博客介绍了一个简单的程序设计案例，该程序能够读取学生的姓名、ID及成绩等信息，按照成绩进行非递增排序，并在指定的成绩区间内筛选出符合条件的学生记录。

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Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

思路：模拟题，照做即可

代码：

#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
using namespace std;
typedef struct Student{
  string name;
  string id;
  int grade;
  Student(string name = "",string id = "",int grade = 0):name(name),id(id),grade(grade){}
}Student;
bool cmp(Student a,Student b)
{
  return a.grade > b.grade;
}
int main()
{
  int n;
  cin>>n;
  vector<Student> v(n);
  for(int i = 0; i < n; i++)
  {
    cin>>v[i].name>>v[i].id>>v[i].grade;
  }
  sort(v.begin(),v.end(),cmp);
  int grade1,grade2;
  cin>>grade1>>grade2;
  bool flag = false;
  for(int i = 0; i < n; i++)
  {
    if(v[i].grade >= grade1 && v[i].grade <= grade2)
    {
      flag = true;
      cout<<v[i].name<<" "<<v[i].id<<endl;
    }
  }
  if(!flag)
    cout<<"NONE"<<endl;
  return 0;
}