Oracle inner/outer/nature join
prerequisite:
create table tab1(id smallint, name char(6), value varchar(10), primary key(id));
create table tab2(id smallint, name char(6), score int, primary key(id));
insert into tab1 values(1, 'AAAAAA', 'aaaaaaaaaa');
insert into tab1 values(2, 'BBBBBB', 'bbbbbbbbbb');
insert into tab1 values(3, 'CCCCCC', 'cccccccccc');
insert into tab2 values(1, 'AAAAAA', 100);
insert into tab2 values(2, 'DDDDDD', 101);
insert into tab2 values(4, 'EEEEEE', 102);
Inner Join
select tab1.id id1,
tab1.name name1,
tab1.value value1,
tab2.id id2,
tab2.name name2,
tab2.score score2
from tab1
inner join tab2
on tab1.id = tab2.id;
ID1 NAME1 VALUE1 ID2 NAME2 SCORE2
---------- ------ ---------- ---------- ------ ----------
1 AAAAAA aaaaaaaaaa 1 AAAAAA 100
2 BBBBBB bbbbbbbbbb 2 DDDDDD 101
Outer Join
Left Outer Join
select tab1.id id1,
tab1.name name1,
tab1.value value1,
tab2.id id2,
tab2.name name2,
tab2.score score2
from tab1
left join tab2
on tab1.id = tab2.id;
ID1 NAME1 VALUE1 ID2 NAME2 SCORE2
---------- ------ ---------- ---------- ------ ----------
1 AAAAAA aaaaaaaaaa 1 AAAAAA 100
2 BBBBBB bbbbbbbbbb 2 DDDDDD 101
3 CCCCCC cccccccccc
Right Outer Join
select tab1.id id1,
tab1.name name1,
tab1.value value1,
tab2.id id2,
tab2.name name2,
tab2.score score2
from tab1
right join tab2
on tab1.id = tab2.id;
ID1 NAME1 VALUE1 ID2 NAME2 SCORE2
---------- ------ ---------- ---------- ------ ----------
1 AAAAAA aaaaaaaaaa 1 AAAAAA 100
2 BBBBBB bbbbbbbbbb 2 DDDDDD 101
4 EEEEEE 102
Full Outer Join
select tab1.id id1,
tab1.name name1,
tab1.value value1,
tab2.id id2,
tab2.name name2,
tab2.score score2
from tab1
full join tab2
on tab1.id = tab2.id
order by tab1.id;
ID1 NAME1 VALUE1 ID2 NAME2 SCORE2
---------- ------ ---------- ---------- ------ ----------
1 AAAAAA aaaaaaaaaa 1 AAAAAA 100
2 BBBBBB bbbbbbbbbb 2 DDDDDD 101
3 CCCCCC cccccccccc
4 EEEEEE 102
Natural Join
select *
from tab1
natural join tab2;
ID NAME VALUE SCORE
---------- ------ ---------- ----------
1 AAAAAA aaaaaaaaaa 100
Notice:
1. natural join automatically bind columns with same column name and column type.
2. same column name with different column type(e.g., char vs. int, but char vs. varchar can work smoothly) will cause natural join failure.
3. return columns contain all distinct column in both tables.
So,
select tab1.* from tab1 natural join tab2;
ERROR at line 1:
ORA-25155: column used in NATURAL join cannot have qualifier
本文通过具体的 Oracle SQL 示例,展示了内连接、左外连接、右外连接、全外连接及自然连接的基本用法,并解释了每种连接类型的特点及其返回结果。
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