# 判断
条件语句的实现,分支判断用分号;,分号后可以跟一个问号作为判断
^x>1? print("yes"); x<1? print("No"); print("I don't know").
^x>y?x;y.
最后以句号作为结尾。
# 循环
@条件?(语句);().
步进for该如何设置呢?
用语法糖
i: 1.
@b:arr\i++\j?
print(b);
print("end").
[感觉这个语法糖真不错]
t_arr: arr.
@b:t_arr++?
print(b);
print("end").
[if语句]
a: 0.
[1]
^a>1?a<=0.
[2]
^a>1?
a<=0.
[3]
^a>1?(
a<=0.
a<=1.
).
[4]
^a>1?(a<=0).
[5]
^a>1?a<=0;a<=1.
[6]
^a>1?(a<=0);(a<=1).
[7]
^a>1?(
^a>2?(
a<=0.
).
).
[这里其实有问题,if不能够无括号包含if与while]
[8]
@a>1?a<=0.
[2]
@a>1?
a<=0.
[9]
@a>1?(
a<=0.
a<=1.
).
[10]
@a>1?(a<=a+1. a<=0).
[11]
@a>1?a<=0;a<=1.
[12]
@a>1?(a<=0);(a<=1).
[13]
@a>1?(
@a>2?(
a<=0.
).
).