Leetcode学习（10）—— Fizz Buzz

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#string #leetcode #buzz #numbers #it

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本文介绍了一个简单的编程挑战：实现一个程序，该程序从1到指定的数字n输出每个数字，但遇到3的倍数时输出Fizz，遇到5的倍数时输出Buzz，同时是3和5的倍数时输出FizzBuzz。通过示例代码展示了如何使用Python解决这个问题。

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Write a program that outputs the string representation of numbers from 1 to n.

But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

Example:

n = 15,

Return:
[
    "1",
    "2",
    "Fizz",
    "4",
    "Buzz",
    "Fizz",
    "7",
    "8",
    "Fizz",
    "Buzz",
    "11",
    "Fizz",
    "13",
    "14",
    "FizzBuzz"
]

# -*- coding:utf-8 -*-
class Solution(object):
    def fizzBuzz(self, n):
        new_list = []
        for i in range(1, n+1):
            if i % 15 == 0:
                new_list.append('FizzBuzz')
            elif i % 5 == 0:
                new_list.append('Buzz')
            elif i % 3 == 0:
                new_list.append('Fizz')
            else:
                new_list.append(str(i))
        return new_list