题目链接 771. Jewels and Stones |
You’re given strings J representing the types of stones that are jewels, and S representing the stones you have. Each character in S is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J are guaranteed distinct, and all characters in J and S are letters. Letters are case sensitive, so "a" is considered a different type of stone from "A".
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
Note:
SandJwill consist of letters and have length at most 50.- The characters in
Jare distinct.
题意
字符串 J 中每个字符为宝石,字符串 S 中的每个字符为自己拥有的石头,想知道自己拥有多少宝石。
区分大小写
思路1
- 使用一个哈希表记录所有的宝石
- 遍历
S中的所有石头,使用ans记录宝石的数量
代码1
class Solution {
public:
int numJewelsInStones(string J, string S) {
bool ch[256] = {true};
for(const auto &it : J)
ch[it] = true;
int ans = 0;
for(const auto &it : S)
if(ch[it])
ans++;
return ans;
}
};
LeetCode 771:宝石与石头的哈希解决方案
该博客介绍了LeetCode第771题——宝石与石头的问题,通过使用哈希表来解决。文章提供了题意解析、思路讲解以及对应的代码实现。
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