Problem
DescriptionThe digital root of a positive integer is found by summing the digits of the integer. If the resulting value is a single digit then that digit is the digital root. If the resulting value contains two or more digits, those digits are summed and the process is repeated. This is continued as long as necessary to obtain a single digit.
For example, consider the positive integer 24. Adding the 2 and the 4 yields a value of 6. Since 6 is a single digit, 6 is the digital root of 24. Now consider the positive integer 39. Adding the 3 and the 9 yields 12. Since 12 is not a single digit, the process must be repeated. Adding the 1 and the 2 yeilds 3, a single digit and also the digital root of 39.
Input
The input file will contain a list of positive integers, one per line. The end of the input will be indicated by an integer value of zero.
Output
For each integer in the input, output its digital root on a separate line of the output.
Sample Input
24
39
0
Sample Output
6
3
代码:
#include<stdio.h>
#include<string.h>
int main()
{
int n,i;
char c[10000];
int sum,m;
while(scanf("%s",c)&&c[0]!='0')
{
sum=0;
for( i=0;i<strlen(c);i++)
sum+=c[i]-'0';
while(sum>=10)
{
m=sum;
sum=0;
while(m>0)
{
sum+=m%10;
m/=10;
}
}
printf("%d\n",sum);
}
return 0;
}
自己编写的代码不通过,百度发现整数所取的范围而不够导致代码审核不通过,多利用字符串数组来解决问题。
本文探讨了数字根的计算方法,通过一个示例问题详细解释了如何通过反复累加整数的各位数字直至得到单个数字的过程。针对初版代码无法通过审核的问题,文章深入分析了原因在于整数取值范围不足,并分享了使用字符串数组解决该问题的有效策略。
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