1082. Read Number in Chinese (25)

原创于 2015-12-19 12:02:33 发布 · 290 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#PAT

PAT 专栏收录该内容

110 篇文章

订阅专栏

本文介绍了一个C++程序，该程序可以将输入的数字转换成对应的汉字金额表示，并且能够处理带有负号的情况。通过使用数组来映射数字到汉字，程序能够适配不同级别的单位，如万和亿。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

#include<cstdio>
#include<cstring>
#include<iostream>
#include<cstdlib>
#include<cmath>
#include<vector>
#include<map>
#include<stack>
#include<queue>
using namespace std;

int main()
{

 const  char *str[9]={"","Shi","Bai","Qian","Wan","Shi","Bai","Qian","Yi"};
const  char *num[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"};
     char s[10];
     vector<const char*> v;
     scanf("%s",s);
     int length=strlen(s);
     if(s[0]=='-')
     {
        v.push_back("Fu");
     for(int i=0;i<length;i++)
        s[i]=s[i+1];
        length--;
     }
     else if(s[0]=='0'&&length==1)
     {
      printf("ling\n");
         return 0;
     }

 int flag=0;
 int cnt=0;
     for(int i=0;i<length;i++)
     {
            if(s[i]!='0')
            {   if(cnt>0&&(length-i-1!=4||s[i]!=0 ))
                    v.push_back("ling");
                v.push_back(num[s[i]-'0']);
                cnt=0;
            }

            else if(s[i]=='0')
            {


            cnt++;
            }
            if(cnt>0&&length-i-1==4&&cnt<4&&s[i]=='0')
            v.push_back(str[length-i-1]);
            else if(i!=length-1)
            {
                if(s[i]!='0')
                v.push_back(str[length-i-1]);

            }

     }
     for(int i=0;i<v.size();i++)
     if(i==0)
        printf("%s",v[i]);
   else
    printf(" %s",v[i]);
   printf("\n");

    return 0;
}