杭电OJ题 1390 Binary Numbers解题报告

本文介绍了一个程序,该程序接收一个正整数n作为输入,并计算并输出其二进制表示中所有1的位置。样例展示了对于输入13,输出为0, 2, 3。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Binary Numbers

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 1953    Accepted Submission(s): 1239



Problem Description
Given a positive integer n, find the positions of all 1's in its binary representation. The position of the least significant bit is 0.


Example

The positions of 1's in the binary representation of 13 are 0, 2, 3.


Task

Write a program which for each data set:

reads a positive integer n,

computes the positions of 1's in the binary representation of n,

writes the result.
 

Input
The first line of the input contains exactly one positive integer d equal to the number of data sets, 1 <= d <= 10. The data sets follow.

Each data set consists of exactly one line containing exactly one integer n, 1 <= n <= 10^6.
 

Output
The output should consists of exactly d lines, one line for each data set.

Line i, 1 <= i <= d, should contain increasing sequence of integers separated by single spaces - the positions of 1's in the binary representation of the i-th input number.
 

Sample Input
1 13
 

Sample Output
0 2 3
 
——————————————————————————————————————————————————
十进制与二进制的转换问题

/****************************
 *Name:Binary Numbers.c
 *Tags:ACM water
 ****************************/

#include <stdio.h>

int main()
{
      int d, num, f, s;
      scanf("%d", &d);
      while(d--) {
	    scanf("%d", &num);
	    s = 0;
	    f = 0;
	    while(num) {
		  if(num % 2 == 1) {
			if(f) {
			      printf(" %d", s);
			} else {
			      printf("%d", s);
			      f = 1;
			}
		  }
		  num /= 2;
		  s++;
	    }
	    printf("\n");
      }
      return 0;
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值