PAT：A1027 Colors in Mars （20 分）_java pat 1027 colors in mars-优快云博客

本文介绍了一个将十进制颜色值转换为火星计算机中使用的13进制RGB颜色值的方法。通过具体的C/C++和Java代码示例，展示了如何实现这一转换，并提供了样例输入输出以验证算法的正确性。

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PAT：A1027 Colors in Mars （20 分）

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:

Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:

For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0 to its left.

Sample Input:

15 43 71

Sample Output:

#123456

代码：

C/C++:

#include<stdio.h>
char str[13] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C'};

int main() {
	int r, g, b;
	scanf("%d %d %d", &r, &g, &b);
	printf("#");
	printf("%c%c", str[r/13], str[r%13]);
	printf("%c%c", str[g/13], str[g%13]);
	printf("%c%c", str[b/13], str[b%13]);	
	return 0;
}

Java：

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        String str = "0123456789ABC";
        int a = in.nextInt(); int b = in.nextInt(); int c = in.nextInt();
        System.out.print("#" + str.charAt(a / 13) + str.charAt(a % 13) 
        + str.charAt(b / 13) + str.charAt(b % 13) + str.charAt(c / 13) + str.charAt(c%13));
    }

}