PAT:A1001 A+B Format （20 分）

最新推荐文章于 2020-09-16 20:18:26 发布

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最新推荐文章于 2020-09-16 20:18:26 发布

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本文介绍了一道名为PAT:A1001 A+B Format的编程题目，该题目要求计算两个整数的和，并以标准格式输出结果，即每三位数字用逗号分隔。文章提供了C/C++及Java两种语言的示例代码，帮助读者理解和实现题目要求。

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PAT:A1001 A+B Format （20 分）

Calculate a+b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −106≤a,b≤106. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

代码：

C/C++:

#include<stdio.h>
#include<math.h>

int main() {
	int a, b, temp, i = 0;
	scanf("%d %d", &a, &b);
	temp = a + b;
	if(temp < 0) {
		printf("-");
		temp = -temp;
	}
	int str[10];
	if(temp == 0) str[i++] = 0; 
	while(temp != 0) {
		str[i++] = temp%10;
		temp = temp/10;
	}
	for(int j = i-1; j >= 0; j--) {
		printf("%d", str[j]);
		if(j != 0 && j % 3 == 0) printf(",");
	}
	return 0; 
}

Java:

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int a = in.nextInt();
        int b = in.nextInt();
        int c = a + b, len = 0;
        if(c < 0) {
            System.out.print("-");
            c = -c;
        }
        int arr[] = new int[10];
        do {
            arr[len++] = c % 10;
            c = c / 10;
        } while (c != 0);
        for (int i = len - 1; i >= 0; i--) {
            System.out.print(arr[i]);
            if(i != 0 && i % 3 == 0) {
                System.out.print(",");
            }
        }
    }
}